Question

20 ml of 0.2 M Al2(SO4)3 is mixed with 20 ml of 0.6 M BaCl2. Concentration of A13+ ion in the solution
will be
I (A) 0.2 M.
(B) 10.3 M
(C) 0.1 M
(D) 0.25 M​

Answer 1

Answer:

A. 0.2M

Explanation:

Al2(SO4)3+BaCl3+  BaCl2   →    BaSO4⏐↓+AlCl3

mEq before mixing is 20×0.2×620×0.6×200

mEq after 0 0 24 24

mEq =M×V (in mL) M× Valency

∴[Al3+]= 24  / 40×3

 =0.2M