Question

20 ml of 0.2M Al2(SO4)3 is mixed with 20ml of 6.6 M BaCl2 , the concertration of Cl - ion in solution is 1) 0.2 2) 6.6 3) 0.02 4) 0.06

Answer 1

Answer:

Twenty ml of 0.2M Al2(SO4)3 is mixed with 20ml of 6.6 M BaCl2 . What is the concentration of Cl - ions in the solution?

Total amount of chloride ion in solution = 2*20mL*6.6mmol/mL = 264 mmol

( We have assumed that no chloride ion is bound to the captions Ba++ and Al+++ which are also present in solution. This is not exactly correct because ion-pairs are also present in the solution.)

Total volume of solution= 20 mL + 20 mL = 40 mL

Concentration (molarity) = 264 mmol/40 mL =6.6 M

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Answer 2

The concentration of chloride ions present in the mixture of  20 ml of 0.2M $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}$ and 20ml of 6.6 M $\mathrm{BaCl}_{2}$ is 6.6 M.

Explanation:

• From the given barium ion concentration is 6.6 M.

• Any solution that has equal amounts of cations and anions. And the solution dissociated into equal amounts of positive and negative ions.

• The barium chloride solution has equal $\mathrm{Ba}^{2+}$ ions and $\mathrm{Cl}^{-}$ ions.

• The solution has 6.6 M $\mathrm{Ba}^{2+}$ ions and therefore, $\mathrm{Cl}^{-}$ ions are also present in 6.6M.