Question

20 ml of 0.5 m HCL is mixed with 20 ml of 6.6 M bacl2 the concentration of Cl- ion in solution is​

Answer 1

Answer:

0mL of 0.2M Al

2

(SO

4

)

3

is mixed with 20mL of 6.6M BaCl

2

Concentration of Cl

−

=

Total volume

Total amount of chloride

Total amount of chloride ion in solution =2×20ml×6.6mmol/ml=264mmol

Total volume =20+20=40mL

∴ Concentration of Cl

−

ion =

40

264

=6.6M .

Answer 2

simply, 6.6M is tge concentration as BaCl2 is given 6.6M which gives Ba2+ and Cl2-