20 ml of 0.5 m HCL is mixed with 20 ml of 6.6 M bacl2 the concentration of Cl- ion in solution is
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2
Answer:
0mL of 0.2M Al
2
(SO
4
)
3
is mixed with 20mL of 6.6M BaCl
2
Concentration of Cl
−
=
Total volume
Total amount of chloride
Total amount of chloride ion in solution =2×20ml×6.6mmol/ml=264mmol
Total volume =20+20=40mL
∴ Concentration of Cl
−
ion =
40
264
=6.6M .
Answered by
0
simply, 6.6M is tge concentration as BaCl2 is given 6.6M which gives Ba2+ and Cl2-
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