Question

20 ml of 1N HCI, 10 ml of N/2
H2SO4, and 30 ml of N/3 HNO3 are mixed together and volume made to1000 ml. Find out the normality of H+ ions in the resulting solution.

1)7/100 N

2)7/200 N

3)7/18 N

4)7/9 N​

Answer 1

Ans 7/200 N

(H+) =20x1+10x0.5+30x0.33/1000

(H+)= 20+5+10/1000 N

= 35/1000 N =7/200 N

Answer 2

As we know M(eq) = N x V

where

M(eq) = equivalent molarity

N = normality of solution

V = volume of solution

Applying this formula for each we get

For HCl----------M(eq) = 1 x 20 = 20M

For H₂SO₄---------M(eq) =  1/2 x 20×1/2 = 5M

For HNO₃----------M(eq) = 1/3 x 30 = 10M

For total soluion, M(eq) = M₁ + M₂ + M₃

M(eq) = 20 + 5 + 10 = 35M

and volume = 1000 mL

Applying same formula M(eq) = N x V

35 = N x 1000

N = 35/ 1000

N = 7/200