20 ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass =294g) for the oxidation of dissolved organic matter. The C.O.D of water sample is
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Answer:
10mL water =1.47×10
−3
g of K
2
Cr
2
O
7
10
6
mL water =1.47g of K
2
Cr
2
O
7
∵49g of K
2
Cr
2
O
7
requires O
2
=89
∴147g of K
2
Cr
2
O
7
will required O
2
=
49
8×147
=24g.
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