Question

20 ml of a water sample required 2.94 mg of K2Cr2O7 (molar mass =294g) for the oxidation of dissolved organic matter. The C.O.D of water sample is

Answer 1

Answer:

10mL water =1.47×10

−3

g of K

2

Cr

2

O

7

10

6

mL water =1.47g of K

2

Cr

2

O

7

∵49g of K

2

Cr

2

O

7

requires O

2

=89

∴147g of K

2

Cr

2

O

7

will required O

2

=

49

8×147

=24g.

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