20 ml of ch4 is completely burnt using 50 ml of o2.the volume of the gas left after cooling to room temperature is
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CH4 + 2 O2 = CO2 + 2 H2O
20 ml of CH4 will consume 40 ml of O2
Therefore a balance of 10 ml of O2
20 ml of CH4 will produce 20 ml of CO2
So the total volume of gas left = 10 + 20 = 30 ml
( Note: 40 ml of water produced will become liquid after cooling to room temperature)
20 ml of CH4 will consume 40 ml of O2
Therefore a balance of 10 ml of O2
20 ml of CH4 will produce 20 ml of CO2
So the total volume of gas left = 10 + 20 = 30 ml
( Note: 40 ml of water produced will become liquid after cooling to room temperature)
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