Question

20 ml of HCL solution is exactly neutralized by 40 ml of 0.05M of NaOH. the pH of HCL solution is​

Answer 1

Explanation:

n-factor of NaOH = 1

n-factor of HCl = 1

As we know, N1 V1=N2V2

(0.1*1)(.02)=(.05*1)*V2

V2=0.04 litre

V2=40ml