Question

20 ml of hydrogen gas at 15°C is heated to 35C at constant pressure.
Find the new volume of hydrogen.
pls help

Answer 1

$\bigstar$ Given

20 ml of hydrogen gas at 15°C is heated to 35°C at constant pressure

$\bigstar$ To Find

The new volume of hydrogen

$\bigstar$ Solution

We know that

Charles's Law

At constant pressure, volume is directly proportional to temperature

Mathematically

$\red{\sf \longrightarrow V \propto T}$

Hence

$\pink{\sf \longrightarrow \dfrac{V_{1}}{V_{2}}=\dfrac{T_{1}}{T_{2}}}$

Here

• V = Volume
• T = Temperature

Units

• V = millilitre (ml)
• T = Kelvin (K)

According to the question

We are asked to find the new volume of hydrogen

Hence

We must find " $\sf V_{2}$"

Therefore

$\sf \longrightarrow V_{2}=\dfrac{V_{1} \times T_{2}}{T_{1}}$

Given that

20 ml of hydrogen gas at 15°C is heated to 35°C at constant pressure

Hence

• V₁ = 20 ml
• T₁ = 15°C = 15 + 273 K = 288 K
• T₂ = 35°C = 35 + 273 K = 308 K

Substituting the values

We get

$\sf \longrightarrow V_{2}=\dfrac{20 \times 308}{288} \ ml$

$\sf \longrightarrow V_{2}=\dfrac{6160}{288} \ ml$

$\sf \longrightarrow V_{2}= 21.38888 \ ml$

Therefore

$\purple{\sf \longrightarrow V_{2}=21.39 \ ml}$

Hence

The new volume of hydrogen = 21.39 ml

Answer 2

Answer:

Given :-

• 20 ml of hydrogen gas at 15°C is heated to 35°C constant pressure.

To Find :-

• What is the new volume of hydrogen.

Formula Used :-

By using Charles's law we know that,

$\boxed{\bold{\large{\dfrac{\sf{V_1}}{\sf{T_1}} =\: \dfrac{\sf{V_2}}{\sf{T_2}}}}}$

where,

• V₁ = First volume
• V₂ = Second volume
• T₁ = First temperature
• T₂ = Second temperature

Solution :-

Given :

✦ V₁ = 20 ml

✦ T₁ = 15°C = 273 + 15 = 288 K

✦ T₂ = 35°C = 273 + 35 = 308 K

Here, the pressure is constant and only the temperature is changed.

According to the question by using the formula we get,

⇒ $\dfrac{\sf{V_1}}{\sf{T_1}}$ = $\dfrac{\sf{V_2}}{\sf{T_2}}$

⇒ $\dfrac{20}{288}$ = $\dfrac{\sf{V_2}}{308}$

⇒ $\sf{V_2} =\: \dfrac{20 \times 308}{288}$

⇒ $\sf{V_2} =\: \dfrac{6160}{288}$

➠ $\sf{V_2} =\: 21.39\: ml$

$\therefore$ The new volume of hydrogen is 21.39 ml .