Question

20 ml of hydrogen gas at 15°C is heated to 35C at constant pressure.
Find the new volume of hydrogen.
pls help

Answer 1

★ Given

20 ml of hydrogen gas at 15°C is heated to 35°C at constant pressure

★ To Find

The new volume of hydrogen

★ Solution

We know that Charles's Law

At constant pressure, volume is directly proportional to temperature

Mathematically

$\red{\sf \longrightarrow V \propto T}$

Hence

$\pink{\sf \longrightarrow \dfrac{V_{1}}{V_{2}}=\dfrac{T_{1}}{T_{2}}}$

Here

V = Volume

T = Temperature

Units

V = millilitre (ml)

T = Kelvin (K)

According to the question

We are asked to find the new volume of hydrogen

Hence

We must find " $\sf V_{2}$ "

Therefore

$\sf \longrightarrow V_{2}=\dfrac{V_{1} \times T_{2}}{T_{1}}$

Given that

20 ml of hydrogen gas at 15°C is heated to 35°C at constant pressure

Hence

V₁ = 20 ml

T₁ = 15°C = 15 + 273 K = 288 K

T₂ = 35°C = 35 + 273 K = 308 K

Substituting the values

We get,

$\sf \longrightarrow V_{2}=\dfrac{20 \times 308}{288} \ ml$

$\sf \longrightarrow V_{2}=\dfrac{6160}{288} \ ml$

$\sf \longrightarrow V_{2}= 21.38888 \ ml$

Therefore,

$\purple{\sf \longrightarrow V_{2}=21.39 \ ml}$

Hence,

The new volume of hydrogen = 21.39 ml

Answer 2

Given :

• 20 ml of hydrogen gas at 15°C is heated to 35°C at constant pressure.

To Find :

• The new volume of hydrogen.

Solution :

Charles's Law says that at constant pressure, volume is directly proportional to temperature.

$\Large \boxed{\pink{\bf Volume \propto Temperature}}$

Therefore,

$\Large \boxed{\pink{\bf \dfrac{V_{1}}{V_{2}}=\dfrac{T_{1}}{T_{2}}}}$

To find the new volume of hydrogen, V₂ :

$\Large \boxed{\pink{\bf V_{2}=\dfrac{V_{1} \times T_{2}}{T_{1}}}}$

We are given that 20 ml of hydrogen gas at 15°C is heated to 35°C at constant pressure.

Therefore,

• V₁ = 20 ml

• T₁ = 15°C = 15 + 273 K = 288 K

• T₂ = 35°C = 35 + 273 K = 308 K

By Substituting the values, We get :

$\bf : \implies V_{2}=\dfrac{20 \times 308}{288} \: ml$

$\bf : \implies V_{2}=\dfrac{6160}{288} \: ml$

$\bf : \implies V_{2}= 21.38888 \: ml$

$\Large \boxed{\pink{\bf V_{2}=21.39 \: ml \: (approx.)}}$

$\pink{\bf The \: new \: volume \: of \: hydrogen = 21.39 \: ml \: (approx.)}$