Question

20 ml of hydrogen measured at 15°c are heated to 35°c. what is the new volume at the same pressure ?​

Answer 1

$\huge\bold{HEY:)-}$

V1= 20ml= 0.02L

T1= 15°C= 288K

V2=?

T2= 35°C= 308K

V1/T1= V2/T2

V2= V1xT2/T1

V2= 6.16/288

V2= 0.0213

V2= 21.3ml

Answer 2

$\huge\bf{\underline{\underline{\mathbf{Answer-}}}}$

$\star{\mathtt{\blue{\underline{Given\: condition:-}}}}$

$\large\bold{ v_{1} = 20ml}$

$\large\bold{ t_{1} = 15 + 273}$

$\large\bold{ = > 288k}$

$\star{\mathtt{\blue{\underline{Final\: condition:-}}}}$

$\large\bold{ v_{2} = ? }$

$\large\bold{ t_{2} = 35 + 273}$

$\large\bold{ = > 308k}$

$\bold{by\:applying\:charles\:law}$

$\large\bold{ = > \frac{ v_{2}}{308} = \frac{20}{288} }$

$\large\bold{ = > v_{2} = \frac{20}{288} \times 308}$

$\large\boxed{ = > 21.38ml}$

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