Question

20 ml propen gas complete fire how much oxyfen volume
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Answer 1

Answer:

f the 20 ml of propane is measured at STP, then:  

1.0 mole of gas at STP has a volume of 22.4 liters = 22400 ml  

20 ml/22400ml = 8.93 x 10^-4 moles of propane.  

Propane is C3H8, so the equation is:  

C3H8 + 5 02 ======> 3 CO2 + 4 H2O  

so, you would need 5 * 8.93x10^-4 moles = 4.46 x 10^-3 moles of oxygen gas, which, at STP, would occupy:  

22400 ml/mole * 4.46x10^-3 moles = 100 ml  

An easier way to calculate the same answer would be to realize that, from the equation:  

C3H8 + 5 O2 ======> 3 CO2 + 4 H2O  

If both gases are measured at STP, then you need five times the volume of oxygen to react one volume of propane, thus:  

5 x 20 ml = 100 ml of oxygen.

Explanation: