Question

20% of an article is damage and thrown away and only 20kg is left.Find its original weight

Answer 1

Answer:

given: 80% = 20kg

20% = 20/80 x 20 =5kg

original weight= 20+5 = 25kg

hope the answer helps

pls mark me as brainliest

Answer 2

Given, Weight of left over article = 20 kg

Percent of article damaged = 20%

To find the original weight of the article, first we should find the percent of left over article.

Percent of left over article = (100 - 20)%

= 80%

Now, we can find the original weight of the article

Let the original weight be y,

$=> 80\% \: of \: y \: = 20$

$=> \frac{80}{100} \times y = 20$

$=> 80y = 100 \times 20$

$=> y = \frac{100 \times 20}{80}$

$=> y = 25kg$

Hence, The Original Weight of the article is 25kgs.

Hope its helpful for you.

Please Mark as Brainlist.⭐⭐⭐