Math, asked by golu77, 1 year ago

20% of doll produce in a factory were defective 25% of the remaining were damaged If 4800 were left over what was the original numbers of dolls?

Answers

Answered by siddhartharao77
115
Let the original number of dolls be x.

Given, Number of defected dolls = 20x/100

Given, Number of Remaining dolls = 80x/100

Number of remaining were damaged = 25% of 80x/100

                                                               = 20x/100

Number of toys left over = 

x - (20/100 * x + 20x/100) = 4800

x - 40x/100 = 4800

100x - 40x/100 = 4800

60x/100 = 4800

x = 4800 * 100/60

   = 8000.

The original number of dolls was 8000.



Hope this helps!

shiva738241: 8000 ...original number of dolls
siddhartharao77: Yes
golu77: bhaiya ek question batao na plizz.....
siddhartharao77: Yes. what is that question Golu
Answered by aayushenterprises15
24

This is the answer

the original numbers of dolls are:8000

hope it help you

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