Question

20 om and 10 om resisters are connected first in series and then in parallel across 10 volt battery. calculate the total resistance and current through 10 om resisters in each circuit​

Answer 1

When both the resistors are connected in series, then,

Net resistance = (20+10) ohms

Now the current flow through the circuit will be

$=\frac{V}{R} =\frac{10}{30}A\\=\frac{1}{3}=0.33A$

When resistors are connected in parallel, then

Net resistance =

$\frac{1}{R} = \frac{1}{R_{1}} +\frac{1}{R_{2} } \\=\frac{1}{10} + \frac{1}{20} = \frac{1+2}{20} ohms\\R = \frac{20}{3}ohms$

Current flows through the circuit =

$\frac{10}{\frac{20}{3} } = 1.5A$