(20) P is a point in the exterior of a circle having centre 0 and radius 24. OP = 25. A tangent from P touches
the circle at Q. Find PQ.
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1
Answer:
the correct answer is 7
Step-by-step explanation:
Given: A circle with center O with radius 24
P is exterior point of a circle
OP = 25
Radius of circle is 24 & A tangent from P touches the circle at Q
Thus, OQ=24
To find: PQ
OP²=PQ²+OQ²
25²= PQ² + 24²
625=PQ² + 576
PQ²= 625 - 576
PQ²= 49
PQ= √49
PQ= 7
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