20 passengers are to travelled by a doubled decked bus which can accommodate 13 in the upper deck and 7 in the lower deck. The number of ways that they can be distributed if 5 refuse to sit in the upper deck and 8 refuse to sit in the lower deck is:
Answers
Answered by
8
refused to sit on upperdeck --->5
refused to sit on lowerdeck --->8
total people remaining to arrange is = 20-13=7
remaining place in upper deck = 5
therefore, no. of ways possible= 7c5 = 21
remaining place in lower deck = 2
therefore, no. of ways possible= 7c2 = 21,also
no. of ways possible is 21.
refused to sit on lowerdeck --->8
total people remaining to arrange is = 20-13=7
remaining place in upper deck = 5
therefore, no. of ways possible= 7c5 = 21
remaining place in lower deck = 2
therefore, no. of ways possible= 7c2 = 21,also
no. of ways possible is 21.
Answered by
1
Answer:
Number of People who refused to sit in upperdeck = 5
Number of People who refused to sit in lowerdeck = 8
Number of people remaining to be arranged = 7
Thus, Number of possible ways = 7c5 = 21
Step-by-step explanation:
Hope it Helps U
Similar questions