20 persons are invited for a party. In how many different ways can they and the host be seated at circular table, if the two particular persons are to be seated on either side of the host?
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Total number of persons in party=21=21
As two persons A and B are to be seated besides the host H, number of arrangements are AHB and BHA.
Taking {A,H,B} as a single element.
nono of persons=19=19
\therefore no∴no of arrangements=(n-1)!=(n−1)!
=18!=18!
\therefore∴Total nono of ways=18!\times 2=18!×2ways of arrangement besides host
=18!\times 2=18!×2
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