20 point
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Answers
Answer:
2tantheta
Explanation:
The acceleration of the block while it is sliding down the upper half of the inclined plane is gsinθ.
If μ is the coefficient of kinetic friction between the block and the lower half of the plane,the retardation of the block while it is sliding down the lower half = −(gsinθ−μcosθ)
For the block to come to rest at the bottom of the inclined plane,the acceleration in the first half must be equal to the retardation in the second half,i.e.
gsinθ=−(gsinθ−μgcosθ)
μcosθ=2sinθ
μ=2tanθ
Hence the correct answer is μ=2tanθ
Answer:
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