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a block of 2 kg mass is being pulled with a force of 10 Newton what is the tension in the rope
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Let mass of rope = mr = 0.5 kg, mass of block = mb = 4 kg, force applied = F = 9 N
Let the tension in the string be T
Common acceleration of the system, ac = F÷(mr+mb) = 9/4.5 = 2 m/s2
For the block to be moving with this acceleration, tension, T = mb.ac = 4*2 = 8 N.
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Anu726:
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Answered by
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Let mass of rope = mr = 0.5 kg, mass of block = mb = 4 kg, force applied = F = 9 N
Let the tension in the string be T
Common acceleration of the system, ac = F÷(mr+mb) = 9/4.5 = 2 m/s2
For the block to be moving with this acceleration, tension, T = mb.ac = 4*2 = 8 N.
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