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PART H: In parts E F and G which data sets ( corretive lenses , glasses , contacts)Show the most similar variation between Doctors?
PART I:Then compare the mean of the two data sets found in part H as a multiple of their variability?
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Answered by
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PartH: Part F and Part G shows the most similar variation bw data sets of doctors as doctor A has the more mean absolute deviation in both glasses and contacts data sets than doctor B.
Part I:in part F mean =6442+6366/20=640.4& in part G mean=977+934/20=95.55
Now comparing both the means of two sets of data_
We get mean of glasses is 6.7022501308 times more than mean of contacts.
Hope this helps you!!
Part I:in part F mean =6442+6366/20=640.4& in part G mean=977+934/20=95.55
Now comparing both the means of two sets of data_
We get mean of glasses is 6.7022501308 times more than mean of contacts.
Hope this helps you!!
asr7:
please ask gettable answers.
Answered by
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Answer: Part F and Part G shows the most similar variation by data sets of doctors as doctor A has the more mean absolute deviation in both glasses and contacts data sets than doctor B.
Step-by-step explanation:
Part I:in part F mean =6442+6366/20=640.4& in part G mean=977+934/20=95.55
Now comparing both the means of two sets of data_
We get the mean of glasses is 6.7022501308 times more than the mean of contacts.
Learn More about Absolute Deviation Below:
https://brainly.com/
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