Question

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An object is launched from a platform. Its height (in meters), x seconds after the launch, is modeled by: h(x)=−5x^2+20x+60 What is the height of the object at the time of launch?

Answer 1

Answer:

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Answer 2

At the time of launch, t=0,

h(0)= -5(0)^2+20(0)+60
= 60

Answer is height of the object at the time of launch is 60meters .