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class 9 physics question
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acceleration=0.1ms^-2
time=2min=2×60=120s
initial speed u=0
a)from first equation of motion speed acquired,
v=u+at
0+0.1×120
12ms^-2
b)from second equation of motion distance travelled
s=ut+0.5at^2
=0×120+0.5×0.1×120×120
=0.1×60×120
=720m
may this helps u
please mark as brainliest
time=2min=2×60=120s
initial speed u=0
a)from first equation of motion speed acquired,
v=u+at
0+0.1×120
12ms^-2
b)from second equation of motion distance travelled
s=ut+0.5at^2
=0×120+0.5×0.1×120×120
=0.1×60×120
=720m
may this helps u
please mark as brainliest
sunny170:
sure
Answered by
2
u= 0 ;a=0.1 m s/2; 2 min=120 s;v=?;s=?
a.using v = u+at, we have
v = 0+0.1*120
v = 12 m s/1
b.using s = ut+1/2 at square, we have
s = 0*120+1/2*0.1(120)square
=0+0.1*14,400/2
s = 720 m
a.using v = u+at, we have
v = 0+0.1*120
v = 12 m s/1
b.using s = ut+1/2 at square, we have
s = 0*120+1/2*0.1(120)square
=0+0.1*14,400/2
s = 720 m
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