20 points. Find the pressure exerted by man weighing 90kg onth ground (a)when he is standing on one feet having an area of 90 cm^2. (b)when he is lying flat. The area of his body is contact with the ground os 0.9 m^2. Given g = 10ms^-2.
Answers
Answered by
1
Answer:
Explpressure, P = Weight of the man/ area.
Weight of the man = 90 Kgf = 90*9.81N = 784.8N
(1) area of the body of the man = 0.9m^2
So, P = 784.8/0.9= 1308 Pa
(2 ) area of the foot of the man = 90cm^2 = 90*10-4 m^2
Find pressure in this case by yourself.anation:
Answered by
0
Answer:
Force exerted by the man (thrust) =mg
=90kg×10ms
−2
=900kgms
−2
=900N
(a) pressure exerted by man while standing =
Area
Force
=
(
10000
90
)m
2
900N
=
90
900×10000
Nm
−2
=10
5
Nm
−2
(b) Pressure exerted by man while lying =
Area
Force
=
0.9m
2
900N
=
9m
2
9000N
=1000Nm
−2
=10
3
Nm
−2
Explanation:
Hope you understood
Pls mark as brainliest
Also pls thanks if it helps
Pls follow me
Attachments:
Similar questions