Question

20 points. Find the pressure exerted by man weighing 90kg onth ground (a)when he is standing on one feet having an area of 90 cm^2. (b)when he is lying flat. The area of his body is contact with the ground os 0.9 m^2. Given g = 10ms^-2.

Answer 1

Answer:

Explpressure, P = Weight of the man/ area.

Weight of the man = 90 Kgf = 90*9.81N = 784.8N

(1)  area of the body of the man = 0.9m^2  

So, P = 784.8/0.9= 1308 Pa

(2 ) area of the foot of the man = 90cm^2 = 90*10-4 m^2  

Find pressure in this case by yourself.anation:

Answer 2

Answer:

Force exerted by the man (thrust) =mg

=90kg×10ms

−2

=900kgms

−2

=900N

(a) pressure exerted by man while standing =

Area

Force

=

(

10000

90

)m

2

900N

=

90

900×10000

Nm

−2

=10

5

Nm

−2

(b) Pressure exerted by man while lying =

Area

Force

=

0.9m

2

900N

=

9m

2

9000N

=1000Nm

−2

=10

3

Nm

−2

Explanation:

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