Question

20 POINTS FOR THIS
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solve for |x^2-2x-8|=2x real values​

Answer 1

Answer:

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

x+2=0. x-4=0

x=-2. x=4