Question

20 points!
Please andswer the Qn.! I'll mark the Answer as the Brainliest!!


P and Q are centres of two circles of radii 12 cm and 3 cm respectively. A and B are points of contact of the common tangent XY. Find the length of AB.

Answer 1

Heyyyaa!

Ur ans:-

Let the required figure be the fig given

Therefore,

Length of OQ will be:-

12+3=15

Now, in ∆POQ ,

/_ POQ = 90°

Therefore, using Pythagoras,

QO^2=PQ^2 + QO^2

= 15 SQUARE + 9 SQUARE (12-3=9)

=306

Therefore, OQ=3√34

Also, AB = OQ ( rectangle )

Therefore, AB= 3√34

Hope it helps :)

Answer 2

Length of OQ will be :

12+3=15

Now, in ∆POQ ,

Angle POQ = 90°

By using Pythagoras,

QO^2=PQ^2 + QO^2

= 15 SQUARE + 9 SQUARE (12-3=9)

=306

Therefore, OQ=3√34

Also, AB = OQ

So, AB= 3√34


Hope this will help u... :-)