Question

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KINDLY SOVE THISSSSS​

Answer 1

Answer:

Explanation:

We are given that the given solution of battery acid contains 24.5% by mass of H2SO4. This means that 100g of the solution contains 24.5g of sulphuric acid and 75.5g of water. Now, the molality of a solution is given by the following relation :

Molality = number of moles of solute / Mass of solvent (in Kg)

Number of moles of H2SO4 present in 24.5g  = mass of H2SO4 / molar mass of H2SO4 

= (24.5 / 98)

= 0.25

The molality of the battery solution will therefore be = (0.25 / 75.5) X 1000

= 3.311

Answer 2

Molality = number of moles of solute / Mass of solvent (in Kg)

Number of moles of H2SO4 present in 24.5g = mass of H2SO4 / molar mass of H2SO4

= (24.5 / 98)

= 0.25

The molality of the battery solution will therefore be = (0.25 / 75.5) X 1000

= 3.311