Math, asked by gangalaxmibehera, 8 months ago

20. PQRS is a parallelogram. Mis the midpoint of
QR. PM is produced to meet SR produced at N.
Prove that SN=2SR. PLEASE answer it ​

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Answers

Answered by abrarmohsin7
2

Answer:

SORRY, I DON'T KNOW EXACTLY THE ANSWER

Step-by-step explanation:

Given that, PQRS is a parallelogram and line SR =SM

To Prove - Line QR = QN

Proof,

∠SRM = ∠RMS     [Since, angles opposite to equal sides of a triangle are equal]

∠QPS = ∠RQN = ∠SRM     [Co-interior angle]

∠SMR + ∠SRM = ∠PSR      [Exterior angle property]   -    (1)

∠SRQ + ∠PSR = 180°          [Since, sum of co-interior angles of a parallelogram is equal to 180°]

⇒ ∠SRQ + ∠SMR + ∠SRM = 180°    [From (1)]

⇒ ∠SRQ = 180° - ∠SMR - ∠SRM     -     (2)

∠QRM = ∠SRQ + ∠SRM      -     (3)

∠NRQ + ∠QRM = 180°        [Linear Pair]

⇒∠NRQ + ∠SRQ + ∠SRM = 180°     [From (3)]

⇒∠NRQ + 180° - ∠SMR - ∠SRM + ∠SRM = 180°    [From (2)]

⇒∠NRQ = ∠SMR

Since, two angels of both triangles are equal and  ∠SRM = ∠SMR,

∠NRQ = ∠SMR = ∠SRM = ∠RNQ    

Therefore, line QR = QN     [ Sides opposite to equal angles of a triangles are equal]

HOPE IT HELPS !!

Answered by monika251276
5

Answer:

IN THE parallelogram PQRS,

PQ=SR

AND PS=QR

NOW IN BETWEEN TRIANGLE QMP AND TRIANGLE MRN,

ANGLE QMP=ANGLE RMN as M is the midpoint.

AND QM=MR as M is the midpoint.

AND PM=MN  as M is the midpoint.

SO WE CAN SAY BOTH THE TRIANGLES ARE CONGRUENT TO EACH OTHER.

THEREFORE, RN=PQ.

NOW, PQ=SR

OR,RN=SR

OR,RN+SR=SR+SR

OR,SN=2SR as (RN +SR=SN)

SO,SN=2SR (PROVED)

       

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