Question

20. Radical centre of x² + y2 - x + 3y - 3 = 0,
x2 + y2 - 2x +2y + 2 = 0 and x²+y2+2x+3y.
9=0 is
1) (2,3) 2) (3, 2) 3) (-2,3) 4) (-3, -2)​

Answer 1

hope the answer helped you

Answer 2

Given :  x² + y² - x + 3y - 3 = 0,    ,   x² + y² - 2x +2y + 2 = 0   and  x²+y² +2x + 3y -9 =0    

To Find : Radical centre

Solution:

Radical centre of three circles drawn on sides of triangle as diameter will be orthocenter of triangle formed by

Radical center is center of a circle which cut all 3 circle orthogonal  

x² + y² - x + 3y - 3 = 0,    Eq1

x² + y² - 2x +2y + 2 = 0   Eq2

x²+y² +2x + 3y -9 =0     Eq3

Eq1 - Eq2

=>  x + y  =  5     Eq4

Eq2 - Eq3

=> 4x + y  =  11     Eq5

Eq5 - Eq4

=> 3x = 6

=> x = 2

& y = 3

( 2, 3) is the Radical centre of  circles

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