20. Read the passage given below and answer any four questions:
Sohan's house has one bedroom hall with kitchen. His son needed a separate room for
study. Thus Sohan planned to construct a new room with length 4m, width 2m and the
height 3 m as shown in the following figure.
The room was separate at the roof of the house. The dimensions of the bricks used are: 25
cm x 10 cm x 5 cm
15 C
25 cm
BRICK
I
STUDY ROOM
1 Total how many bricks will be required? (1 m3 =1000000 em)
Answers
Step-by-step explanation:
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Given :- Sohan's house has one bedroom hall with kitchen. His son needed a separate room for study. Thus Sohan planned to construct a new room with length 4m, width 2m and the height 3 m as shown in the following figure.
The room was separate at the roof of the house. The dimensions of the bricks used are: 25cm x 10 cm x 5 cm
A) Total how many bricks will be required ?
a. 30000
b. 40000
C 28800
d. 27000
B) How many bricks will be used on both walls along the length (length-4 m) ?
a. 19200
b. 20200
C 18800
d. 17000
C) What is the volume of the room ?
a. 24 m³
b. 12m³
C. 20m³
d. 15 m³
D) What is the area of the floor ?
a. 10 m²
b. 12 m²
c. 8 m²
d. 9 m²
Solution :-
we know that,
Volume of cuboid = Length * Breadth * Height .
1m³ = 1000000 cm³ .
so,
→ volume of room = 4 * 2 * 3 = 24 m³ (Ans.C) (Option a)
now, Let us assume that, x number of bricks are required on both walls along the length .
then,
→ Volume of room = x * volume of each brick
→ 24 * 1000000 = x * 25 * 10 * 5 .
→ 24000000 = 1250x
→ x = 19,200 (Ans.B) (Option a)
also, Let us assume that, y number of bricks are required on both walls along the breadth .
then,
→ (Volume of room/2) = y * volume of each brick
→ (24 * 1000000)/2 = y * 25 * 10 * 5 .
→ 12000000 = 1250y
→ y = 96,00
therefore,
→ Total number of bricks required = 19,200 + 96,00 = 28,800 (Ans.A) (Option c).
hence,
→ Area of the floor = Length * width = 4 * 2 = 8 m² . (Ans.D) (Option c) .
