Question

20. The adjoining figure shows an isosceles AOAB with sides OA = AB = 10 units
and OB=12 units. Find the coordinates of the vertices of triangle AOB

Answer 1

Answer:

O = (0,0) B = (12, 0) A=(6, 8)

Step-by-step explanation:

• from the figure we understand that one of the vetices is in the origin

• since point B is on X-axis the year coordinate of the point is 0. The point is 12 units away from away from the origin or the Y-axis. Therefore the X coordinate is 12. implies that the point is (12,0)
• By appling Pythagorean rule in triangle OAM.

AM =

$\sqrt{oa { }^{2} - om { }^{2} }$

=

$\sqrt{10 {}^{2} - 6 { }^{2} }$

=8

we already know that (from figure) M is 6 units away from Your axis. Now we know that A is 8 units away from x axis ( since AM is 8 units and M is on the x axis)

Therefore the coordinates of A is (6,8)

Answer 2

Answer:

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