20. The ages of Sonal and Manoj are in the ratio 7:5. Ten years hence, the ratio of their ages
will be 9: 7. Find their present ages.
21. Five years ago a man was seven times as old as his son. Five years hence, the father will be
three times as old as his son. Find their present ages.
Answers
20 .
Given :
The ages of Sonal and Manoj are in the ratio 7:5 .Ten years hence, the ratio of their ages will be 9: 7
To Find :
Present ages
Solution :
Let present age of Sonal and Manoj be 7x , 5x
Ten years hence, the ratio of their ages will be 9: 7
Present age of Sonal , 7x = 35 years
Present age of Manoj , 5x = 25 years
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21 .
Given :
Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son
To Find :
Present ages
Solution :
Five years ago ,
Let age of son be x
Age of man = 7x
Five years hence, the father will be three times as old as his son
Present age of son , x + 5 = 10 years
Present age of Father , 7x + 5 = 40 years
Or
Alternate Method :
Let present age of father be x
Present age of son be y
Five years ago ,
Father's age = x - 5
Son's age = y - 5
Five years ago a man was seven times as old as his son
After 5 years ,
Father's age = x + 5
Son's age = y + 5
Five years hence, the father will be three times as old as his son
Solve (2) - (1) ,
Sub. y value in (2) ,
Present age of father , x = 40 years
Present age of son , y = 10 years