20. The area of a rectangular carpet is 120.m’ and its perimeter is 46 m. the length of its diagonal is
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Step-by-step explanation:
l × b = area
120 = l × b - 1
2 ( l + b ) = perineter
2 ( l + b ) = 46
l + b = 23
b = 23 - l
from 1st equation
23 - l = 120 /l
so
- l^2 + 23l - 120
l^2 + 15 l + 8l - 120
-l( l - 15 ) + 8 ( l - 15)
(l - 15)(8 -l)
from this
l = 15 and b = 8
as angle of rectangle is 90 ⁰
heb ce phythagorean triplet
so
let diagonal be d
d² = l² + b²
= 15² + 8²
= 225 + 64
d² = 289
d = underoot 289
d = 17 m
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