20.
The average force necessary to stop a
hammer with 25 N-S momentum in 0.05
second expressed in newton is
1) 500 2) 125 3) 50 4) 25
Answers
Answered by
20
Answer:- 500
solution:-
Force = Impulse/time
Force = Impulse/time = 5/0.05
Force = Impulse/time = 5/0.05
Force = Impulse/time = 5/0.05 =500N
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Answered by
4
Answer:
Yup
Explanation:
u r right vanshi।।।।।
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