20
The chord of a circle is equal to its
radius. Then the angle subtended by
the chord at the major arc of the circle
is *
(1 Point)
Answers
Answered by
3
Answer:
Solution. Hence, the angle subtended by the chord at a point on the minor arc is 150° and also at a point on the major arc is 30°.
Answered by
1
Answer:
Given,
AB is equal to the radius of the circle.
In △OAB,
OA=OB=AB= radius of the circle.
Thus, △OAB is an equilateral triangle.
∠AOC=60°
Also, ∠ACB=
2
1
∠AOB=
2
1
×60°=30°
ACBD is a cyclic quadrilateral,
∠ACB+∠ADB=180° ∣ Opposite angles of cyclic quadrilateral
⇒∠ADB=180°−30°=150°
Thus, angle subtend by the chord at a point on the minor arc and also at a point on the major arc are 150° and 30° respectively.
Step-by-step explanation:
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