Question

20. The distance between the points (2-3) and (k.9) is 13 units. Find k
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Answer 1

Step-by-step explanation:

According to distance formula,

(2-k)2+(-3-9)2=(13)2

4+k2-4k+144=169

k2-4k+148=169

k2-4k-21=0

k2-7k+3k-21=0

k(k-7)+3(k-7)=0

k can either be 7 or -3..