Question

20. The length of the rectangle exceeds its breadth by 3 cm. If the length and breadth are each increased by 2 cm, then the area of new rectangle will be 70 sq. cm more than that of the given rectangle. Find the length and breadth of the given rectangle.​

Answer 1

:et length be ...x

breadth be...x-3

x × (x-3)=xsq.-3x. ....eq

(x+2)×(x-3+2)=(x)×(x-3)+70

x+2)×(x-1)=x sq. - 3x + 70

xsq. - x - 2=x sq. -3x+70

xsq-xsq-x+3x=70+2

2x=72

x=36

length=36

breadth=33

Answer 2

Step-by-step explanation:

Let b be the breadth

length = b+ 3

If length and breadth increased by 2cm

new area is 70 sq cm more

i.e., b(b + 3) + 70 = (b + 2)(b +5)

b2 + 3b + 70 = b2 + 2b + 5b + 10

4b = 60

b = 15

I=15+3 = 18.