Question

20. The mean of four numbers a,b,c,d is 100.
c=70, then the mean of the remaining nom-
bers is​

Answer 1

Answer:

$= > \frac{a + b + c + d}{4} = 100 \\ = > \frac{a + b + d +7 0}{4} = 100 \\ = > a + b + d + 70= 100 \times 4 \\ = > a + b + d = 400 - 70 \\ = > a + b + d = 330$