Question

20. The near and far points of a person are at 40 cm and 250 cm respectively. With aided eye, the maximum distance upto which he can clearly see is approximately____cm
(given: Focal length of the lens used = + 200/3 cm).
Please give explanation.​

Answer 1

Explanation:

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Answer 2

Answer:

The lens should be such that it shifts the image of object at 25cm from eye to the near point of the defected person.

The lens should be such that it shifts the image of object at 25cm from eye to the near point of the defected person.Hence the lens would follow the following lens equation,

f1=P= v1 − u1 =

−0.41 −

−0.251 =1.5D