Question

20. The ratio between the number of boys and girls in a class is 8: 7. If there are 48 boys in the
class, find the
(a) number of girls in the class.
(b) total number of students in the class.​

Answer 1

Answer:

Let the common ratio between number of boys and girls be x

Number of boys =7x

Number of girls =5x

As per the question,

Number of boys = Number of girls +8

7x=5x+8

Transpose 5x to LHS, we will get

7x−5x=8

2x=8

Divide both sides by 2

x=4

No. of boys =7x=7×4=28

No. of girls =5x=5×4=20

Total class students 28+20=48

Please mark me as a

Answer 2

Given: The ratio between the number of boys and girls in a class is 8: 7 and there are 48 boys in the class

Need To Find: number of girls in the class and total number of students in the class.

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⧠ Let , the number of Boys in the class be 8x and the number of girls be 7x

${ \sf{ \underline{ \bigstar \: According \: to \: the \: question : }}}$

We know that,

• ➪ No. of boys = ${\bf{\gray{48}}}$

→ Let's find the value of x and then multiply it with 7 to find the number of girls

${\bf{ \blue{\leadsto \: 48 = 8x}}} \\ \\ \\ {\bf{ \blue{\leadsto \: x = \cancel\frac{48}{8} \: }}} \\ \\ \\ {\bf{ \blue{\leadsto \: x= 6 \bigstar}}}$

→ Now, let's find the number of girls :

$\longrightarrow \tt \: the \: no.of \: girls \: = 6 \times 7 \\ \\ \\ \longrightarrow \tt \: the \: no.of \: girls \: =42 \bigstar \: \:$

$\orange{ \underline{ \frak{Hence, The \: number \: of \: girls \: are \: 42 }}}$

★Now , let's find the total students in the class:

$\longrightarrow \tt \: the \: no.of \: students \: = \: 42 + 48 \\ \\ \\ \longrightarrow \tt \: the \: no.of \: students \: = 90 \dag \: \: \: \: \: \: \: \: \: \:$

$\orange{ \underline{ \frak{Hence,The \: number \: of \: students \: are \: 90 }}}$

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