Question

20. The smallest number which when divided by 30, 45,
75 and 60 leaves a remainder of 21, 36, 66 and 51
respectively is
A. 900
B. 909
C. 891
None of these.​

Answer 1

Answer:

The answer is none of this

Step-by-step explanation:

May this helps you

Answer 2

The correct option is C) 891.

Step-by-step explanation:

Consider the provided information.

Find the L.C.M of the numbers 30, 45,  75 and 60.

30 = 2 × 3 × 5

45 = 3 × 3 × 5

75 = 3 × 5 × 5

60 = 2 × 2 × 3 × 5

Thus, the L.C.M = 2 × 2 × 3 × 3 × 5 × 5 = 2² × 3² × 5² = 900

900 is the least number which is divisible by 30, 45, 75 and 60.

Now subtract the remainders from each of their divisors.

30 – 21 = 9

45 – 36 = 9  

75 – 66 = 9

60 – 51 = 9

Thus, the required smallest number is = 900 – 9 = 891.

Hence, the correct option is C) 891.

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The smallest number which leaves remainder 5 when divided by 15 20 and 35 .