Math, asked by TanishkaSharma400, 9 months ago

20. The sum of the present ages of a mother and her
daughter is 60 years. When the mother attains her
husband's present age, the ratio of her husband's
age and her daughter's age would be 2 : 1. Find the
present ageſ of the daughter. (in years)

Answers

Answered by k047

5

Let the present ages of Daughter be "D'', mother be "M" & husband be "H".

Given, D + M = 60....(i)

Let after 'x' years, mother attains the age of husband(daughter's father)

So after 'x' years:

Daughter's age = D + x

Mother's age = M + x = H (present age of husband or his age 'x' years back)

Husband's age = H + x

Also given, Husband's age : daughter's age = 2:1

(H+x)/(D+x) = 2/1

H + x = 2*(D + x)

H = 2*D + 2x-x = 2*D + x

H = 2D + x ......(ii)

We also had M+x = H

So, M + x = 2D + x

M = 2D ....(iii)

Substitute (iii) in (i)

(i)== M + D = 60

2D + D = 60

3D = 60

D = 20 years.

Hence present age of daughter is '20' years.

Hope this helps

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Answered by itzcupycake

2

$\Huge{\bold{\mathrm{\underline{\red{ANSWER}}}}}$

Let the present ages of Daughter be "D'', mother be "M" & husband be "H".

Given, D + M = 60....(i)

Let after 'x' years, mother attains the age of husband(daughter's father)

So after 'x' years:

Daughter's age = D + x

Mother's age = M + x = H (present age of husband or his age 'x' years back)

Husband's age = H + x

Also given, Husband's age : daughter's age = 2:1

(H+x)/(D+x) = 2/1

H + x = 2*(D + x)

H = 2*D + 2x-x = 2*D + x

H = 2D + x ......(ii)

We also had M+x = H

So, M + x = 2D + x

M = 2D ....(iii)

Substitute (iii) in (i)

(i)== M + D = 60

2D + D = 60

3D = 60

D = 20 years.

Hence present age of daughter is '20' years.

Hope this helps

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