Question

20.The tens and units digit of the number are the same. When the number is
added to its reverse, the sum is 110. What is the number?

Answer 1

Answer:

hey here is your solution

so pls mark it as brainliest

so let the required two digit number be 10x+y

wherein digit at tens place is x and that of units is y

so thus reversed number=10y+x

now according to first condition

x=y (1)

according to the second condition

10x+y+10y+x=110

ie 11x+11y=110

so x+y=10 (2)

thus now substitute value of x from (1) in (2)

we get 2y=10

ie y=5

now substitute value of y in any of two equations

we get x=5

so our assumed two digit number=10x+y

=(10×5)+5

=50+5

=55

hence required two digit number is 55

Answer 2

Given :

• The tens and units digit of the number are the same. When the number is added to its reverse, the sum is 110.

To find :

• The number.

Solution :

Let tens digit be x.

As question says, Tens digit = Units digit = x.

• The number will be = 10x + x
• Reverse will be = 10x + x

According to the question,

→ 10x + x + 10x + x = 110

→ 22x = 110

→ x = 110/22

→ x = 5

→ The value of x = 5

Now, Putting the value of x in the equation,

→ 10x + x

→ 10(5) + 5

→ 50 + 5

→ 55

Therefore, the number is 55.

___________________

Let's verify :-

We can verify the value of the number by substituting it in the equation "10x + x + 10x + x = 110" if the left hand side will be equal to the right hand side then the value of the number is correct.

→ 10x + x + 10x + x = 110

Taking LHS,

→ 10(5) + 5 + 10(5) + 5 = 110

→ 50 + 50 + 10 = 110

→ 110 = 110

LHS = 110

RHS = 110

LHS = RHS

Hence, Verified!