Physics, asked by siric2cdwk, 2 days ago

20. The upper and lower fixed points of a faulty mercury thermometer are 210°F and 30 °F respectively. If body temperature reads as 40 °C then temp of body in faulty thermometer is
1) 22°F
2) 80°F
3) 100°F
4) 104°F​

Answers

Answered by nehadahiya248
0

Answer:

Correct option is D)

180

F−32

=

U−L

F−L

180

F−32

=

210−34

F−34

180

F−32

=

176

F−34

45

F−32

=

44

F−34

45F−45×34=44F−44×32

45F−44F=1530−1408

F=122℉

Answered by CyberBorealis
0

Answer:

Correct option is D)

180F−32=U−LF−L

180F−32=210−34F−34

180F−32=176F−34

45F−32=44F−34

45F−45×34=44F−44×32

45F−44F=1530−1408

F=122℉

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