Question

20. There are
factors in (4)4 x (7)5 x (11)?​

Answer 1

Total number of factors  $4^{4}$ × $7^{5}$ × $11^{1}$  is "108".

Step-by-step explanation:

The factor of $4^{4}$ × $7^{5}$ × $11^{1}$

= $2^{8}$ × $7^{5}$ × $11^{1}$

[ ∵ 4 = 2 × 2]

Number of factors = (p + 1)(q + 1 ) (r + 1)

Here, p =8, q = 5 and r = 1

∴ Number of factors = (8 + 1)(5 + 1 ) (1 + 1)

= 9 × 6 × 2

=54 × 2

= 108

Hence, total number of factors  $4^{4}$ × $7^{5}$ × $11^{1}$  is "108".