20 times a positive integer is less than its square by 96 what is the integer
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let positive integer be x
20x=x^2-96
x^2-20x-96=0
x^2+4x-24x-96
x(x+4)-24(x+4)
(x-24)(x+4)
hence, as x is a positive integer
x=24
20x=x^2-96
x^2-20x-96=0
x^2+4x-24x-96
x(x+4)-24(x+4)
(x-24)(x+4)
hence, as x is a positive integer
x=24
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