Question

20. Two men standing on the same side of a tower in a straight line with it, measure the angles
of elevation of the top of the tower as 25 and 50% respectively. If the height of the tower is
70 m, find the distance between the two men
325​

Answer 1

Answer:

sorry

Step-by-step explanation:

Please mark a brainlist

Answer 2

Answer:

According to the given statement, the figure will be as shown alongside in the attached picture in which PQ is tower so PQ=70m.

A and B be the position of 2 people,such that <PAQ=25° and <PBQ=50°.

In ∆PAQ

tan 25°=PQ/AC

(The value of tan 25° is 0.4663)

Therefore,

0.4663=70/AQ

that is,

AQ=70/0.4663 m

= 150.118 m

In ∆PBQ,

tan 50°=PQ/BQ

(The value of tan 50° is 1.1918)

Therefore,

1.1918=70/BQ

that is,

BQ=70/1.1918 m

=58.735 m

Therefore,

The Distance between the two people

=AB=AQ=BQ

=(150.118-58.735)m

=91.38 m

hope it's helpfull