Question

20) Two roads of width 3 m run perpendicular
to each other in the middle of a garden as
shown in the figure. The garden is of
length 100 m and
breadth 80 m. The
roads are laid at a cost
of 11 per m2 and the​

Answer 1

Step-by-step explanation:

The total amount required is Rs. 43,186.

Step-by-step explanation:

In the attached figure ABCD is rectangular field with 100m length and 80m breadth.

Area of the field = 100 × 80 = 8000 m^{2}m

2

width of the road is 3m.

Area of the road = (100 ×3) + (80 × 3 ) - (3 × 3)

= 300 + 240 - 9 = 531 m^{2}m

2

∴ Area of the garden = Area of the field - Area of the road

= 8000 - 531 = 7469 m^{2}m

2

∵cost of road per m^{2}m

2

= 11 Rs.

∴total cost of road = 11 × 531 = 5841 Rs.

∵ cost of garden levelling per m^{2}m

2

= 5 Rs.

∴total cost of garden levelling = 5 × 7469 = 37,345 Rs.

∴Total amount required = 5841 + 37,345 = 43,186 Rs.