Question

20
Value of positive real root of p(x) is...... if p(x)
(1 Point)
x2 + 5x - 300 = 0
​

Answer 1

answer =15

Step-by-step explanation:

x2+5x-300=0

x2+20x-15x-300=0

x(x+20)-15(x+20)=0

(x+20)(x-15)=0

x+20=0;x-15=0

therefore x=-20/15

as -20 is negative positive real root =15