Physics, asked by rishitsingh70, 6 months ago

20 waves pass through a point in 2 seconds. If the distance between one crest and
adjacent trough is 1.5 m. Calculate (a) the frequency. (b) the wavelength

Answers

Answered by Anonymous
6

(b) Wave length = 1.5m as wavelength is the distance b/t crest & adjacent through

(a) Frequency =  \sf \huge \frac{No.\:of\:oscillations}{time}

 \sf⇒\frac{20}{2}

⇒ 10Hz

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