Question

20) What is the heat in joules required to raise the temperature of 25 grams of water from 0° C to 100° C? What is the heat in Calories? (Specific heat of water = 4.18 J/g° C)

Answer 1

Answer:

249.761 kilo calories

Explanation:

Given :

Specific heat of water c  = 4.18 J / g C

Mass m = 25 g

Temperature Δ T = 100 C

We know :

Q = m c Δ T

where Q  denotes Heat energy

Q = 25 × 4.18 × 100 J

Q = 10,45,000 J or 1045 kJ

We know :

1 Joule  = 1 / 4.12 calories

10,45,000 J = 249.761 kilo calories

Q =  249.761 kilo calories

Hence we get answer.